Logout succeed
Logout succeed. See you again!

On the holonomy group of hypersurfaces PDF
Preview On the holonomy group of hypersurfaces
ON THE HOLONOMY GROUP OF HYPERSURFACES OF SPACES OF CONSTANT CURVATURE 5 OGNIAN KASSABOV 1 0 2 Abstract. WeclassifyhypersurfacesMn ofmanifoldsofconstantnonzerosectionalcurva- b ture according their restricted homogeneous holonomy groups. It turns out that outside of e the evident cases (restricted holonomy group SO(n) and flat submanifolds) only two cases F arise: restricted holonomy group SO(k)×SO(n−k) (when M is locally a product of two 0 space forms) and SO(n−1) (when M is locally a product of an (n−1)-dimensional space 2 form and a segment). ] G D . 1. Introduction h t a The holonomy groups are fundamental analytical objects in the theory of manifolds and m especially in the theory of Riemannian manifolds. The holonomy group of a Riemannian [ manifold reflects for example on local reducibility of the manifold. In [6] M. Kurita classifies 2 the conformal flat Riemannian manifolds according their restricted homogeneous holonomy v group. 7 2 There exists a similarity between the conformal flat Riemannian manifolds and the hyper- 6 surfaces of a Riemannian manifold, see e.g. a remark of R. S. Kulkarni in [5]. So it is natural 6 to look for a result in the submanifold geometry, analogous to the Kurita’s theorem. In [3] . 1 S. Kobayashi proves that the holonomy group of a compact hypersurface of En+1 is SO(n). 0 4 Generalizations of of Kobayashi’s result are obtained by R. Bishop [1] and G. Vranceanu [8]. 1 In this paper we consider analogous question for hypersurfaces of non-flat real space forms : v according their holonomy groups. Namely we prove: i X Theorem 1. Let Mn (n ≥ 3) be a connected hypersurface of a space Mn+1(ν) of constant r a positive sectional curvature ν. Then the restricted homogeneous holonofmy group Hp of Mn in any point p is in general the special orthogonal group SO(n). If H is not SO(n) at any p point p ∈ Mn, then one of the following cases appears: a) H = SO(k)×SO(n−k), 1 < k < n−1 and Mn is locally a product of a k-dimensional p space of constant curvature ν + λ2 and an (n − k)-dimensional space of constant sectional curvature ν +µ2, with ν +λµ = 0; b) H = SO(n−1) and Mn is locally a product of an (n−1)-dimensional space of constant p sectional curvature and a segment. A similar theorem for complex manifolds is proved in [7]. 2. Preliminaries. Let Mn+1 be an(n+1)-dimensional Riemannian manifoldwith metric tensor g and denote by ∇ ifts Riemannian connection. It is well known that if Mn+1 is of constant sectional e f Key words and phrases. Space of constant curvature, hypersurface, holonomy group. 2010 Mathematics Subject Classification: 53B25. 1 2 OGNIANKASSABOV curvature ν, then its curvature operator R has the form e R(x,y) = νx∧y , e where the operator ∧ is defined by (x∧y)z = g(y,z)x−g(x,z)y . Such a manifold is denoted by Mn+1(ν). Now let Mn be a hypersurface of Mn+1(ν) and denote by ∇ its Riemannian confnection. Then we have the Gauss formula f ∇ Y = ∇ Y +σ(X,Y) X X for vector fields X,Y on Mn, wheere σ is a normal-bundle-valued symmetric tensor field on Mn, called the second fundamental form of Mn in Mn+1. Let ξ be a unit normal vector field. Then the Weingarten formula is f ∇ ξ = −A X x ξ e and the operator A is related to σ by ξ g(σ(X,Y),ξ) = g(A X,Y) = g(A Y,X) . ξ ξ Suppose that we have fixed a normal vector field ξ. Then we shall write A insteed of A . ξ The equations of Gauss and Codazzi are given respectively by R(X,Y) = ν(X ∧Y)+AX ∧AY , (∇ A)Y = (∇ A)X , X Y R denoting the curvature operator of Mn. It is known that the Lie algebra of the infinitesimal holonomy group at a point p of a Riemannian manifold M is generated by all endomorphisms of the form (∇kR)(X,Y;V ,...,V ) , 1 k where X,Y,V ,...,V ∈ T M and 0 ≤ k < +∞ [4]. Moreover if the dimension of the infin- 1 k p itesimal holonomy group is constant, this group coincides with the restricted homogeneous holonomy group [4]. 3. Proof of Theorem 1. Let p be an arbitrary point of Mn. We choose an orthonormal basis e ,...,e of T M, 1 n p which diagonalize the symmetric operator A, i.e. Ae = λ e i = 1,...,n . i i i Then by the equation of Gauss we obtain (3.1) R(e ,e ) = (ν +λ λ )e ∧e . i j i j i j First we note that Mn cannot be flat at p. Indeed if Mn is flat, we obtain from (3.1) ν +λ λ = 0 for all i 6= j. Since n > 2 this implies easily ν +λ2 = 0, and because of ν > 0 i j 1 this is a contradiction. Since Mn is not flat at p, there exist i 6= j, such that ν+λ λ 6= 0. Then (3.1) implies that i j e ∧e belongs to the Lie algebra h of H . As in [6] we denote by SO[i ,...,i ] the subgroup i j p p 1 k of SO(n), which induces the full rotation of the linear subspace, generated by e ,...,e and i1 ik fixes the remaining vectors. Denote also by so[i ,...,i ] the Lie algebra of SO[i ,...,i ]. Then 1 k 1 k according to the above argument H contains SO[i,j]. p ON THE HOLONOMY GROUP OF HYPERSURFACES 3 If H contains SO(n), then H = SO(n), because the restricted homogeneous holonomy p p group H of a Riemannian manifold is a subgroup of SO(n), see [2]. p Let H is not SO(n). Then there exist k, 2 ≤ k ≤ n−1 and indices i ,...,i , such that H p 1 k p contains SO[i ,...,i ] but doesn’t contain SO[i ,...,i ,u] for u 6= i ,...,i . Without loss of 1 k 1 k 1 k generality we can assume that H contains SO[1,...,k], but does not contain SO[1,...,k,u] p for u > k. Let us suppose that h contains so[a,u] for some a ∈ {1,...,k} and u ∈ {k + 1,...,n}. p Since [e ∧e ,e ∧e ] = e ∧e b a a u b u it follows that the Lie algebra h contains e ∧ e for b = 1,...,k. Hence h contains p b u p so[1,...,k,u], which is a contradiction. Consequently h doesn’t contain so[a,u] for any a = 1,...,k; u = k +1,...,n. Then (3.1) p implies (3.2) ν +λ λ = 0 a = 1,...,k; u = k +1,...,n. a u Hence, using ν 6= 0, we obtain λ = ... = λ and λ = ... = λ . Denote λ = λ ; θ = λ . 1 k k+1 n 1 k+1 Then by (3.2) ν +λθ = 0, λ 6= 0, θ 6= 0 and it follows easily λ 6= θ, ν +λ2 6= 0, ν +θ2 6= 0. In a neighborhood W of p we consider continuous functions Λ ,...,Λ , such that for any 1 n point q ∈ W the numbers Λ (q),...,Λ (q) are the eigenvalues of A. Since ν + λ2 6= 0, 1 n ν +θ2 6= 0, then in an open subset V of W containing p we have ν +Λ (q)Λ (q) 6= 0 a,b = 1,...,k ; a b ν +Λ (q)Λ (q) 6= 0 u,v = k +1,...,n . u v Hence H containsSO[1,...,k]andSO[k+1,...,n]. Supposethatν+Λ (q)Λ (q) 6= 0forsome q a u a = 1,...,k, u = k +1,...,n. Then h contains e ∧e , so as before h contains so[1,...,k,u] q a u q and analogously h contains so(n), which is not possible. So ν +Λ (q)Λ (q) = 0. Hence as q a α before we find Λ (q) = ... = Λ (q) , Λ (q) = ... = Λ (q) . 1 k k+1 n Consequently in a neighborhood V of p there exist a number k and continuous functions Λ(q),Θ(q) such that Λ(q) 6= Θ(q) and (3.3) Λ (q) = ... = Λ (q) = Λ(q) 6= 0 , Λ (q) = ... = Λ (q) = Θ(q) 6= 0 1 k k+1 n for q ∈ V. Since Mn is connected k is a constant on Mn. Consequently (3.3) holds on Mn. On the other hand using ν +ΛΘ = 0 and the fact that kΛ+(n−k)Θ = trA is smooth we conclude that Λ and Θ are smooth functions on Mn. Define two distributions T (q) = {x ∈ T (M) : Ax = Λ(q)x} , 1 q T (q) = {x ∈ T (M) : Ax = Θ(q)x} . 2 q It follows directly that T and T are orthogonal and for X,Y ∈ T , Z,U ∈ T we have 1 2 1 2 R(X,Y) = (ν +Λ2)X ∧Y , ν R(Z,U) = (ν +Λ2)Z ∧U , Λ2 R(X,Z) = 0 . 4 OGNIANKASSABOV We choose local orthonormal frame fields {E ,...,E } of T and {E ,...,E } of T and we 1 k 1 k+1 n 2 denote n ∇ E = Γ E . Ei j X ijs s s=1 Then Γ = −Γ for all i,j,s = 1,...,n, in particular Γ = 0. As before let a,b,c ∈ ijs isj ijj {1,...,k} and u,v ∈ {k +1,...,n}. From the second Bianchi identity we have (∇ R)(E ,E )+(∇ R)(E ,E )+(∇ R)(E ,E ) = 0 a b u b u a u a b and hence k E (Λ2)E ∧E +(ν +Λ2) {Γ E ∧E −Γ E ∧E } u a b X buc a c auc b c c=1 n ν +(ν +Λ2) (Γ −Γ )E ∧E +Γ E ∧E −Γ E ∧E = 0 . X nΛ2 abv bav u v uav v b ubv v ao v=k+1 Consequently we obtain (3.4) E (Λ2) = (ν +Λ2){Γ +Γ } , u aau bbu (ν +Λ2)Γ = 0 uva for all a 6= b. Since ν +Λ2 6= 0 we find Γ = 0, so T is parallel. uva 2 Let n−k ≥ 2. Then analogously to the above T is also parallel. Now (3.4) implies that 1 Λ doesn’t depend on E and analogously Θ doesn’t depend on E . Hence, using ν+ΛΘ = 0 u a we conclude that Λ and Θ are constants. So we obtain the case a) of our Theorem. Let n−k = 1. We shall show that under the assumption H 6= SO(n) the distribution T p 1 is again parallel. By the Codazzi equation we have (∇ A)(E ) = (∇ A)(E ) . a b b a This implies E (Λ)E +(Λ−Θ)Γ E = E (Λ)E +(Λ−Θ)Γ E . a b abn n b a ban n Hence E (Λ) = 0 for a = 1,...n−1. Now from a (∇ A)(E ) = (∇ A)(E ) a n n a we obtain n−1 E (Λ)E +(Λ−Θ) Γ E = 0 . n a X anc c c=1 Hence we derive (3.5) E (Λ) = (Λ−Θ)Γ , n aan (Λ−Θ)Γ = 0 for c 6= a . acn Since Λ 6= Θ the last equality implies Γ = 0 for a 6= c. On the other hand (3.5) implies acn Γ = Γ . If Γ = 0, then T is parallel and from (3.5) E (Λ) = 0, so Λ is a constant. aan bbn aan 1 n Because of ν +ΛΘ 6= 0 it follows that Θ is a constant too. Hence we obtain the case b) of our Theorem. Let us suppose that Γ 6= 0. We compute directly aan (∇ R)(E ,E ) = (ν +Λ2)Γ E ∧E . a a b aan n b Hence E ∧E ∈ h and as before it follows that SO(n) = H , which is not our case. This n b p p proves Theorem 1. ON THE HOLONOMY GROUP OF HYPERSURFACES 5 Remark. Inthesameway we canconsider thecasewhere Mn+1(ν) isofconstant negative sectional curvature ν. Then we obtain f Theorem 2. Let Mn (n ≥ 3) be a connected hypersurface of a space Mn+1(ν) of constant negative sectional curvature ν. Then the restricted homogeneous holonofmy group H of Mn p in any point p is in general the special orthogonal group SO(n). If Mn is not flat and H is p not SO(n) at any point p ∈ Mn, then one of the following cases appears: a) H = SO(k)×SO(n−k), 1 < k < n−1 and M is locally a product of a k-dimensional p space of constant curvature ν + λ2 and an (n − k)-dimensional space of constant sectional curvature ν +µ2, with ν +λµ = 0 b) H = SO(n−1) and M is locally a product of an (n−1)-dimensional space of constant p sectional curvature and a segment. References [1] R.Bishop,Theholonomyalgebraofimmersedmanifoldsofcodimensiontwo,JournalofDiffer.Geometry 2(1968), 347-353. [2] A. Borel and A. Lichnerowicz, Groups d’holonomie des vari´et´es riemanniennes, C. R. Acad. Sci. Paris 234(1952), 1835-1837. [3] S. Kobayashi,Holonomy group of hypersurfaces, Nagoya Math. Journal 10(1956),9-14. [4] S. Kobayashi and K. Nomizu, Foundations of differential geometry, Vol. I, John Wiley and Sons, New York, 1963. [5] R. S. Kulkarni, Equivalence of K¨ahler manifolds and other equivalence problems, Journal of Differ. Geometry 9(1974), 401-408. [6] M. Kurita,On the holonomygroupof the conformallyflat Riemannianmanifold. NagoyaMath. Journal 9(1955), 161-171. [7] K. Nomizu and B. Smyth, Differential geometry of complex hypersurfaces II, J. Math. Soc. Japan 20(1968), 498-521. [8] G. Vranceanu, Sur les groupes d’holonomie des espaces Vn plong´es dans En+p sans torsion, Revue Roumaine de Math. Pures et Appl. 19(1974), 125-128. Department of Mathematics and Informatics University of Transport 158 Geo Milev Str. 1574 Sofia, Bulgaria E-mail address: [email protected]